프로그래머스 코딩테스트 입문 파이썬 lv.0 (6)

배열 회전시키기
https://school.programmers.co.kr/learn/courses/30/lessons/120844

def solution(numbers, direction):
    answer = []
    if direction == "right":
        answer.append(numbers[-1])
        for i in range(1, len(numbers)):
            answer.append(numbers[i-1])
    else:
        for i in range(len(numbers)-1):
            answer.append(numbers[i+1])
        answer.append(numbers[0])
        
    return answer

# 다른 사람의 풀이
def solution(numbers, direction):
    if direction == "right":
        answer = [numbers[-1]] + numbers[:len(numbers)-1]
    else:
        answer = numbers[1:] + [numbers[0]]
    return answer

 

외계행성의 나이
https://school.programmers.co.kr/learn/courses/30/lessons/120834

def solution(age):
    answer = []
    abc = 'abcdefghijklmnopqrstuvwxyz'
    age = str(age)
    for i in range(len(age)):
        num = int(age[i])
        answer.append(abc[num])
    return ''.join(answer)

# 다른 사람의 풀이
def solution(age):
    change = ['a','b','c','d','e','f','g','h','i','j']
    age = list(str(age))
    return ''.join([change[int(i)] for i in age])

 

인덱스 바꾸기
https://school.programmers.co.kr/learn/courses/30/lessons/120895

• list로 변환

def solution(my_string, num1, num2):
    mylist = list(my_string)
    a = mylist[num1] 
    b = mylist[num2]
    mylist[num1] = b
    mylist[num2] = a
    my_string = ''.join(mylist)
    return my_string